Determine the pH of the following acid/ base solutions.
Formulae
pH = -log10[H+]
pOH = -log10[OH-]
pH + pOH = 14
Complete the following
| No. | Solution | Concentration | Dissociation equation | pH |
|
1
|
Hydrochloric acid | 0.0010 M | HCl(aq) → H+(aq) + Cl-(aq) | |
|
2
|
Hydrochloric acid | 1.20 x 10-4 mol L-1 | HCl(aq) → H+(aq) + Cl-(aq) | |
|
3
|
Hydrochloric acid | 0.10 mol L-1 | HCl(aq) → H+(aq) + Cl-(aq) | |
|
4
|
Sodium hydroxide | 0.100 M | NaOH(aq) → Na+(aq) + OH-(aq) | |
|
5
|
Calcium hydroxide | 0.0010 mol L-1 | Ca(OH)2(aq) → Ca2+(aq) + 2OH-(aq) | |
|
6
|
Aluminium hydroxide | 0.0020 M | Al(OH)3(aq) → Al3+(aq) + 3OH-(aq) | |
|
7
|
Nitric acid | 0.230 M | HNO3(aq) → H+(aq) + NO3-(aq) | |
|
8
|
Sulfuric acid | 0.0020 mol L-1 | H2SO4(aq) → 2H+(aq) + SO42-(aq) | |
|
9
|
Phosphoric acid | 2.34 x 10-3 mol L-1 | H3PO4(aq) →3H+(aq) + PO43-(aq) | |
|
10
|
Nitric acid | HNO3(aq) → H+(aq) + NO3-(aq) | 3 | |
|
11
|
Sulfuric acid | H2SO4(aq) → 2H+(aq) + SO42-(aq) | 1 | |
|
12
|
Phosphoric acid | H3PO4(aq) →3H+(aq) + PO43-(aq) | 2.4 | |
|
13
|
Sodium hydroxide | NaOH(aq) → Na+(aq) + OH-(aq) | 8.6 | |
|
14
|
Calcium hydroxide | Ca(OH)2(aq) → Ca2+(aq) + 2OH-(aq) | 11.5 | |
|
15
|
Aluminium hydroxide | Al(OH)3(aq) → Al3+(aq) + 3OH-(aq) | 10.2 | |
|
16
|
Barium hydroxide | 0.020 M | ||
|
17
|
Hydrochloric acid | 1.8 | ||
|
18
|
Sodium hydroxide | 2.0 M | ||
|
19
|
Aluminium hydroxide | 3.33 x 10-5 mol L-1 | ||
|
20
|
Hydrochloric acid | 3.64 | ||
|
21
|
Magnesium hydroxide | 12 | ||
|
22
|
Sulfuric acid | 2.0 mol L-1 | ||
|
23
|
Calcium hydroxide | 0.154 mol L-1 | ||
|
24
|
Phosphoric acid | 4.5 | ||
|
25
|
Sodium hydroxide | 9 | ||
|
26
|
Beryllium hydroxide | 0.10 M | ||
|
27
|
Phosphoric acid | 0.00234 mol L-1 | ||
|
28
|
Lithium hydroxide | 6.0 x 10-2 mol L-1 | ||
|
29
|
Aluminium hydroxide | 13.3 | ||
|
30
|
Sulfuric acid | 2.5 |